Question

please help me with my hw​

Answer 1

Answer:

1. we know AOB is a straight line it means 180*

then angle AOC=180*-45=135*

1. PQR Is a straight line Angle XOP is 180*

XOP =x+15+3x+25=4x+40

180=4x+40

4x=180-40

4x=140

x=140/4

x=35*

then angle XOP= x+15=35+15=50*

YOP=3x+25=3*35+25

=105+25

=130*

(3) angle PQR IS 180*

sum of all angles =60+15+40+x

180=115+x

x=180-115

x=65*

(4) angle AB. Is

Answer 2

Answer: Exercise 17 B:

1.135 °

2.50;130 °

3.65 °

Step-by-step explanation:

1.∠AOC=180°-45°(linear pair)

            =135°

2.∠XOP+∠XOY=180°(linear pair)

     x+15+3x+25=180°

             4x+40°=180°

                    4x=180°-40°

                      x=140/4

                      x=35°

∠XOP=x+15=50°

∠YOP=3x+25°=130°

3.  x=180°-60°-15°-40°

   x =65°

plz mark as brainliest only one brainliest answer needed to go next rank plz

 4th question alone the right side of the diagram is not shown so I cant see it