please help me with my question
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here it is. if any problem mssg me
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NinjaD3stroyer:
thx
welcome bro
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In the given figure AB || CD and EF || GH.
Since the opp. sides of a quadrilateral are parallel to each other so, PQSR is a parallelogram.
Angle APR +Angle QPR =180°(linar pair)
=>110°+AngleAPR=180°
=>AngleAPR=180-110
=70°
So t=70°(opp. angles of a parallelogram are equal)
x=60°(vertically opp. angles )
y=x(alternet interior angles)
y=60°
z=t(alternate interior angles)
z=70°
Since the opp. sides of a quadrilateral are parallel to each other so, PQSR is a parallelogram.
Angle APR +Angle QPR =180°(linar pair)
=>110°+AngleAPR=180°
=>AngleAPR=180-110
=70°
So t=70°(opp. angles of a parallelogram are equal)
x=60°(vertically opp. angles )
y=x(alternet interior angles)
y=60°
z=t(alternate interior angles)
z=70°
bro you to are a brain lieast
thx broo
from him
well i wanted to ask one question to him. why u wrote formula for angles of a parallelogram. it would have been solved without it. it is correct but there was no need of it
thx for answering. I like people who answer
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