Math, asked by sayandeep20102006dey, 9 months ago

Please help me with my question as soon as possible.....​

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Answered by raushan6198
1

Answer:

 {( {x}^{a + b} )}^{a - b}  \times ( { {x}^{b + c}) }^{b - c}  \times ( { {x}^{c + a}) }^{c - a}  \\  =  {x}^{(a + b)(a - b)}  \times  {x}^{(b + c)(b - c)}  \times  {x}^{(c + a)(c - a)}  \\  =  {x}^{ {a}^{2} -  {b}^{2}  }  \times  {x}^{ {b}^{2}  -  {c}^{2} }  \times  {x}^{ {c}^{2}  -  {a}^{2} }  \\  =  {x}^{ {a}^{2}  -  {b}^{2} +  {b}^{2}  -  {c}^{2}   +  {c}^{2}  -  {a}^{2} }  \\  =   {x}^{0}  \\  = 1 \:  \:  \: ans

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