Chemistry, asked by SargamParashar, 1 year ago

Please help me with question 10 (a).​

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Answered by Shrutiarora
0
Phone is reduced and C is oxidised ....
SargamParashar: Thankyou mate for your answer but I had doubt in question (a).
Answered by pranav6131
1

In both the test tubes hydrogen gas is formed. The HCl is strong acid then acetic acid so more hydrogen gas is formed in test tube A which results in vigorous fizzing.

Mg + HCL = Mgcl2 + H2

Mg + CH3COOH =  Mg(CH3COO)2 + H2

hope this helps

SargamParashar: Thankyou mate for your answer.
pranav6131: your welcome
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