Please help me with question 10 (a).
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Phone is reduced and C is oxidised ....
SargamParashar:
Thankyou mate for your answer but I had doubt in question (a).
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In both the test tubes hydrogen gas is formed. The HCl is strong acid then acetic acid so more hydrogen gas is formed in test tube A which results in vigorous fizzing.
Mg + HCL = Mgcl2 + H2
Mg + CH3COOH = Mg(CH3COO)2 + H2
hope this helps
Thankyou mate for your answer.
your welcome
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