Question

PLEASE HELP ME WITH QUESTION 2 OF TRIANGLES CHAPTER I WILL MAKE SURE THAT YOU ARE MARKED AS BRIANLIEST

Answer 1

Answer:

in ∆ACE and ∆BCD

<A=<B (given)

AC=BC (given)

<C=<C (common)

Therefore by ASA criteria 2∆'s are congruent

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Answer 2

Step-by-step explanation:

2). In ∆ACE and ∆ BCD

Angle A = Angle B ( given )

AC = BC ( given )

Angle C = Angle C ( common )

by ASA Congresse,

∆ ACE =~ ∆BCD

By C.P.C.T AE = BD

proved ∆ ACE =~ ∆ BCD

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Correct Answer.