Question

Please help me with question no. 12​

Answer 1

✌✌✌ Hey ✌✌✌

Your Solution : -

Given Polynomial is

✴ x² - 4x + K

✴ Product of zeros = c/a

✴ K= 3

The polynomial is

p(x) = X² - 4x + 3

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Answer 2

GIVEN :-

f( x ) = x^2 - 4x + k

Zero of f(x) = 3

TO FIND :- Value of ' k '

SOLUTION :-

Whenever the zero of a polynomial is replace with the variable then the result must be equal to zero.

Hence it becomes,

$f(x) = {x}^{2} - 4x + k \\ \\ f(3) = {3}^{2} - 4 \times 3 + k = 0$

Now we shall solve linear equation to get the value of k.

${3}^{2} - 12 + k = 0 \\ \\ \\ \implies 9 - 12 + k = 0 \\ \\ \\ \implies - 3 + k = 0 \\ \\ \\ \implies \boxed{k = 3}$

HENCE THE VALUE OF K is 3