Question

please help me with rhis

Answer 1

sorry I can't do this

Answer 2

$(\frac{3}{4})^{x}$ × $(\frac{4}{3})^{-7}$ = $(\frac{3}{4})^{2x}$

$(\frac{3}{4})^{x}$ × $(\frac{3}{4})^{7}$ = $(\frac{3}{4})^{2x}$

$(\frac{3}{4})^{x + 7}$ = $(\frac{3}{4})^{2x}$

When bases are same, we equate the powers

x + 7 = 2x

x - 2x = 7

-x = 7

x = -7