Please help me with the question
Answers
Given - In triangleABC, CF||AD
line l intersect side
AB and BC at point C and F respectively
To Prove - BD/CD=AB/AC
Construction - Draw seg CF||AD such that A-F-B
Proof - In triangleABC and triangleFCD
A(triFBC)/A(triFCD)=BC/CD ----------(1) Areas proportionate to bases
In A(triABC) and A(triACD)
A(triABC)/A(triACD)=AB/AC ----------(2) Areas proportionate to heights
segCF is common base in triFCD
and triCFA
segCF||segAD
hence,triFCD and triCFA have
equal heights
A(triFBC)/A(triFCD)=A(triABC)/
A(triACD)
BC/CD=AB/AC ---------from(1)&(2)
HOPE IT HELP.....
MARK AS BRAINIST......
FOLLOW ME.......
