Question

please help me with the question​

Answer 1

Answer:

∠BAO = ∠DCO [ Alternate angle]

∠BAO = 2x

By ASP of a triangle

∠B + ∠ A + ∠O =180°

3X + 10° + 2X + 3X + 10° = 180°

5X + 10° + 3X + 10° = 180°

8X + 20° = 180°

8X = 180° - 20°

8X = 160°

X = 160°/8

X = 20