Math, asked by minatibera4, 27 days ago

Please help me with the question. NO SCAM!!

I have three children. One child is the same age as the first number in my age, another child is the same as the second number in my age and the third child is the same age as the sum of the two numbers in my age. None of the children are of same age, and total of me and my children's age is 45.

Answers

Answered by 5aayushatewary5

Answer:

You can put this solution on YOUR website!

x = tenths digit in your age

y = units digit in your age

x and y are positive whole numbers AND they are single digits (0 through 9)

your age = 10x+y

child1's age = x

child2's age = y

child3's age = x+y

sum of the three children's ages = (x)+(y)+(x+y) = 2x+2y

Sum of childrens' ages + parent's age = (2x+2y) + (10x+y) = 12x+3y = 45

12x+3y = 45

4x+y = 15

y = -4x+15

Now make a table for y = -4x+15

Since x is a single digit, this means x is a whole number from 0 to 9

x y

0 15

1 11

2 7

3 3

4 -1

5 -5

6 -9

7 -13

8 -17

9 -21

Notice how y is a positive whole number, AND a single digit, when x = 2 or x = 3. The other x values either have y being a double digit number or with y being a negative number. So ignore those other rows.

If x = 2, then y = 7

Parent's age = 27

Child1's age = 2

Child2's age = 7

Child3's age = 2+7 = 9

Sum of ages of parent+children = 27+2+7+9 = 45

If x = 3, then y = 3

Parent's age = 33

Child1's age = 3

Child2's age = 3

Child3's age = 3+3 = 6

Sum of ages of parent+children = 33+3+3+6 = 45

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So your age is either 27 or 33. Either age works.

Answered by shivvakumar