Question

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$( {a + b + c) }^{2} = {12}^{2} \\ {a }^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca = 144 \\ 64 + 2(ab + bc + ca) = 144 \\ 2(ab + bc + ca) = 144 - 64 \\ ab + bc + ca = 40 \\ {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca) = \\ (12)(64 - 40) = 12 \times 24 = 288$