Physics, asked by xXx007, 1 year ago

Please help me with this...

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Answered by JunaidMirza
2
Retardation of car will be equal to -μg

Use equation of motion
v² - u² = 2aS

S = u² / (2 μg)
= (54 × 5/18 m/s)² / (2 × 0.20 × 10 m/s²)
= 56.25 m

Car will travel distance of 56.25 m
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