Question

Please help me with this ​

Answer 1

Answer:

x= 3

Step-by-step explanation:

${27}^{2x - 1} = {243}^{3 } \\ {3}^{6x - 3} = {3}^{15} \\ = > 6x - 3 = 15 \\ = > 6x = 18 = > x = 3$

Answer 2

$\star\:\:\:\sf\large\underline\blue{Question:-}$

• Find the value of x when $\sf {27}^{2x - 1} = {243}^{3}$

$\star\:\:\:\sf\large\underline\blue{Solution:-}$

Given,

$\sf {27}^{2x - 1} = {243}^{3}$

$\sf \implies { ({3}^{3} )}^{2x - 1} = {( {3}^{5} )}^{3}$

$\sf \implies ({3}^{6x - 3} ) = ( {3}^{ 15} )$

Comparing base, we get,

$\sf 6x - 3 = 15$

$\sf \implies 6x = 18$

$\sf \implies x = 3$

$\star\:\:\:\sf\large\underline\blue{Answer:-}$

• The value of x is 3.