Question

please help me with this​

Answer 1

Answer:

92°

Step-by-step explanation:

as AB || DE

AND AE TRANSVERSAL

ANGLE BAC = ANGLE CED = 35

BY ANGLE SUM PROPERTY IN TRIANGLE CDE

CDE + CED + DCE = 180°

53° + 35° + DCE = 180°

DCE = 180° - 88°

= 92°

Answer 2

Answer:

angle D = 53° , Angle E = 35° and angle C = 92°

Step-by-step explanation:

Given : Angle BAC = 35 and Angle CDE = 53

To find : All the measure of angle DCE

Solution : Since AB//DE and AE is transversal

Angle BAE = Angle AED = 35 ° ( Alternate angle )

Angle AED = Angle DEC = 35° (Alternate angle )

In ∆ DCE,

Angle D = 53°

Angle E = 35°

Angle D + Angle E + Angle C = 180°

53 +35+Angle C = 180°

Angle C = 180-88

Angle C = 92° Ans

Hence Angle D = 53° , Angle E = 35° and Angle C = 92°

Hope this will help you