Physics, asked by RK242, 1 year ago

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Answered by Ramanarrora
1
a)Electric field on one side of a charged body is E1 and electric field on the other side of the same body is E2. If infinite plane charged body has a uniform thickness, then electric field due to one surface of the charged body is given by,

E1=-sigma/2∈n --------1

Where,

n= Unit vector normal to the surface at a point

sigma= Surface charge density at that point

Electric field due to the other surface of the charged body,

E2= -sigma/2∈n -----------2

Electric field at any point due to the two surfaces,

E2-E1= sigma/2∈n +sigma/2∈n= sigma/∈n
(E2-E1).n= sigma/∈---------3

Since inside a closed conductor, E1 = 0,

E=E2=- sigma/2∈n

Therefore, the electric field just outside the conductor is sigma/∈



(b) When a charged particle is moved from one point to the other on a closed loop, the work done by the electrostatic field is zero. Hence, the tangential component of electrostatic field is continuous from one side of a charged surface to the other
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