Question

please help me with this​

Answer 1

$\large\sf\underline{Given\::}$

Equation :

• $\sf\:\frac{2x+5}{3}=3x-10$

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$\large\sf\underline{To\:find\::}$

• Value of x

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$\large\sf\underline{Solution\::}$

$\sf\:\frac{2x+5}{3}=3x-10$

• Cross multiplying

$\sf\twoheadrightarrow\:3(3x-10)=2x+5$

• Multiplying the terms and removing brackets

$\sf\twoheadrightarrow\:9x-30=2x+5$

• Now transposing +2x from RHS to LHS , it becomes -2x

$\sf\twoheadrightarrow\:9x-2x-30=5$

• Calculation over like terms in LHS

$\sf\twoheadrightarrow\:7x-30=5$

• Now transposing -30 from LHS to RHS , it becomes +30

$\sf\twoheadrightarrow\:7x=5+30$

$\sf\twoheadrightarrow\:7x=35$

• Now transposing 7 to RHS , it goes to the denominator

$\sf\twoheadrightarrow\:x=\frac{35}{7}$

• Reducing the fraction to lower terms

$\sf\twoheadrightarrow\:x=\cancel\frac{35}{7}$

$\small{\underline{\boxed{\mathrm\red{\twoheadrightarrow\:x=\:5}}}}$ ★

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$\large\sf\underline{Verifying\::}$

Not sure about the ansWers !? Let's verify it.

We would substitute the value of x as 5 in the given equation. Doing so if we get LHS = RHS our answer would be correct.

‎$\sf\:\frac{2x+5}{3}=3x-10$

• Plugging the value of x as 5

‎$\sf\rightarrow\:\frac{2(5)+5}{3}=3(5)-10$

‎$\sf\rightarrow\:\frac{2 \times 5+5}{3}=3 \times 5-10$

‎$\sf\rightarrow\:\frac{10+5}{3}=15-10$

‎$\sf\rightarrow\:\frac{15}{3}=5$

‎$\sf\rightarrow\:\cancel\frac{15}{3}=5$

‎$\sf\rightarrow\:5=5$

‎$\bf\rightarrow\:LHS=RHS$

‎$\large{\mathfrak\green{hence\:verified\:!!}}$

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!! Hope it helps !!