Question

please help me with this​

Answer 1

Answer:

container 2 can hold 290ml more water than container 1

Explanation:

Given

For container 1

length=9cm

breath=6cm

height=5cm

For container 2

length=8cm

breath=7cm

height=10cm

Solution

volume of container 1

$volume \: of \: container \: 1$

$= 9 \times 6 \times 5$

$= 270 {cm}^{3}$

$volume \: of \: container \: 2$

$= 8 \times 7 \times 10$

$560 {cm}^{3}$

$volume \: of \: container \: 1 < volume \: of \: container \: 2$

$volume \: of \: container \: 1 = 270 {cm}^{3}$

$container \: 1 \: can \: hold= 270 ml$

$volume \: of \: containr \: 2 = 560 {cm}^{3}$

$container \: 2 \: can \: hold \: = 560ml$

$560 - 270 = 290$

Therefore container 2 can hold 290ml more water than container 1