Question

please help me with this​

Answer 1

♡Question no.1 :

=>To find

○The number

=>Given:

○Three times the number decreased by 5 gives the result 16.

=>Assuming:

○let the number be x

=>Solution:

○ATQ

$= > 3x - 5 = 16 \\ = > 3x = 16 + 5 \\ = > 3x = 21 \\ = > x = \frac{21}{3} = 7$

Answer:

○x =7

♡Question no.2:

=>To find:

○The multiples

=>Given:

○Sum of three consecutive multiples 3 is 333.

=>Assuming:

○let the three consecutive multiples be x,x+3 and x+9

=>Solution:

○ATQ

=>x+(x+3)+(x+9)=333

=>x+x+3+x+6=333

=>3x+9=333

=>3x=333-9

=>3x=324

$= > x = \frac{324}{3} = 108$

○Therefore, three consecutive multiples are

108,(108+3),(108+6)

=>108,111,114

=>Answer:

○108,111,114

hope it helps....