Math, asked by arunareddyk, 2 months ago

please help me with this​

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Answers

Answered by Umra01
8

Step-by-step explanation:

45 is the answer of this question

Answered by jasmeenkaursra982
1

Answer:

Consider an arbitrary regular polygon of nn sides an example of which is shown above. Join all the vertices to the centre to get nn isosceles triangles.

Let ∠OAB=∠OBA=∠OBC=xo.∠OAB=∠OBA=∠OBC=xo.

⇒∠AOB=yo=180o−2xo.⇒∠AOB=yo=180o−2xo.

A−B−D⇒∠ABD=180o.A−B−D⇒∠ABD=180o.

Further, ∠ABD=∠OBA+∠OBC+∠CBD.∠ABD=∠OBA+∠OBC+∠CBD.

⇒∠OBA+∠OBC+∠CBD=180o.⇒∠OBA+∠OBC+∠CBD=180o.

⇒2xo+∠CBD=180o⇒∠CBD=180o−2xo.⇒2xo+∠CBD=180o⇒∠CBD=180o−2xo.

⇒∠CBD=∠AOB=yo.⇒∠CBD=∠AOB=yo.

Each side of the polygon contributes an angle of yoyo to the centre and the sum of all these angle is equal to 360o.360o.

⇒⇒ Number of sides of the polygon, n=360y.n=360y.

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