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Answer 1

Answer:

Condition for the pair of system to have unique solution a1/a2 ≠ b1/b2 Let the equations be, a1x + b1y + c1 = 0 a2x + b2y + c2 = 0 Since, x = – 1 and y = 3 is the unique solution of these two equations, then It must satisfy the equations – a1(-1) + b1(3) + c1 = 0 – a1 + 3b1 + c1 = 0 …(i) and a2(- 1) + b2(3) + c2 = 0 – a2 + 3b2 + c2 = 0 …(ii) Since for the different values of a1, b1, c1 and a2, b2, c2 satisfy the Eqs. (i) and (ii). Hence, infinitely many pairs of linear equations are possible.Read more on Sarthaks.com - https://www.sarthaks.com/878806/write-pair-linear-equations-which-has-the-unique-solution-how-many-such-pairs-can-you-write