Question

please help me with this

Answer 1

hello mate!........

$given...... \\ ( \frac{3}{4} ) {}^{6} \times ( \frac{16}{9} ) {}^{5} = ( \frac{4}{3} ) {}^{x + 2} \\ \\ ( \frac{4}{3} ) {}^{ - 6} \times ( \frac{4 {}^{2} }{3 {}^{2} } ) {}^{5} = ( \frac{4}{3} ) {}^{x + 2} \\ \\ ( \frac{4}{3} ) {}^{ - 6} \times ( \frac{4}{3} ) {}^{10} = ( \frac{4}{3} ) {}^{x + 2} \\ \\ we \: know......... \\ = > x {}^{a} \times \: x {}^{b} = x {}^{a + b} \\ = > if \: \: \: \: \: x {}^{a } = x {}^{b} \\ then..... \\ a = b \\ \\ ( \frac{4}{3} ) {}^{ - 6 + 10} = ( \frac{4}{3} ) {}^{x + 2} \\ \\ ( \frac{4}{3} ) {}^{4} = ( \frac{4}{3} ) {}^{x + 2} \\ \\ 4 = x + 2 \\ \\ x = 4 - 2 \\ \\ x = 2 \\ \\ hope \: it \: helps \: u \: dear.....$