Please help me with this 6th question
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2
here is your answer........
answer:
Average speed = total distance / total time,
Distance travelled in 20 min = 18/3 = 6 km,
Let the distance travelled in 40 min be x km ,
(20 min = 1/3 of an hour, 40 min = 2/3 of an hour)
Then : 24 =( x + 6)/(2/3 + 1/3), = x+6/1,
X + 6 = 24km, x = 18km , now let the speed required be y, then we know that y = 18/(2/3)
( speed = distance/time) so y = 18 *3/2 km/hr
Y = 27 km/hr, hope you understood. Cheers !!!
Feel free to point out any mistakes as I am too just a learner.
hope it will help u plzz mark it as BRAINLIEST
answer:
Average speed = total distance / total time,
Distance travelled in 20 min = 18/3 = 6 km,
Let the distance travelled in 40 min be x km ,
(20 min = 1/3 of an hour, 40 min = 2/3 of an hour)
Then : 24 =( x + 6)/(2/3 + 1/3), = x+6/1,
X + 6 = 24km, x = 18km , now let the speed required be y, then we know that y = 18/(2/3)
( speed = distance/time) so y = 18 *3/2 km/hr
Y = 27 km/hr, hope you understood. Cheers !!!
Feel free to point out any mistakes as I am too just a learner.
hope it will help u plzz mark it as BRAINLIEST
sauravkumar78:
wlc sister
Hey
Here why have u taken 3
by mistake sorry
Here in 18/3... why 3 is taken
but u can applied the method i have done for the answer
That only I m also asking
In the second step why u have divided 18 by 3????
Answered by
1
Hey dear friend here your smart answer ::
Average speed = total distance / total time,
Distance travelled in 20 min = 18/3 = 6 km,
Let the distance travelled in 40 min be x km ,
(20 min = 1/3 of an hour, 40 min = 2/3 of an hour)
Then : 24 =( x + 6)/(2/3 + 1/3), = x+6/1,
X + 6 = 24km, x = 18km , now let the speed required be y, then we know that y = 18/(2/3)
( speed = distance/time) so y = 18 *3/2 km/hr
Y = 27 km/hr, hope you understood.
Average speed = total distance / total time,
Distance travelled in 20 min = 18/3 = 6 km,
Let the distance travelled in 40 min be x km ,
(20 min = 1/3 of an hour, 40 min = 2/3 of an hour)
Then : 24 =( x + 6)/(2/3 + 1/3), = x+6/1,
X + 6 = 24km, x = 18km , now let the speed required be y, then we know that y = 18/(2/3)
( speed = distance/time) so y = 18 *3/2 km/hr
Y = 27 km/hr, hope you understood.
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