Please help me with this....
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Step-by-step explanation:
Let the semi-perimeter of the triangle be s.
Let the sides of the triangle be a, b and c.
HENCE,
s – a = 8
s – b = 7
s – c = 5
Adding all the above equations, we get
(s – a) + (s – b) + (s – c) = 8 + 7 + 5
⇒ 3s – (a + b + c) = 20
⇒ 3s – 2s = 20
⇒ s = 20 cm
Thus the semi-perimeter is 20 cm
SO THE AREA OF Δ = √s(s-a)(s-b)(s-c)
∴ AREA OF Δ = √20×8×7×5
∴ AREA OF Δ = 20√14 cm²
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