Please help me with this geometry sums!
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In the quadrilateral AzBCD add all the angles
x+70+3x-20+2x+5+2x-15=360
(husum of all 4 angles of a quadrilateral is 360 degree)
8x+40=360
8x=360-40=320
x=40
angle ABC=3x-20=3×40-20=100
APD=5x and APC=x (opposite angles)
Add all the 4 angles
5x+x+5x+x=360
12x=360
x=30
APD=5x=5×30=150
Do the last one in the same way as done the 1st one
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