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Answers
We know that volume of cylinder is
π * r^2 * h......
Remember that r is squared....
So, a small increase in r can result in big changes in volume....
For example, if radius is tripled, volume becomes 9 times.....
So, here cylinder with base 14 and height 7 will have more volume.....
WITH CALCULATIONS
1st Cylinder's volume = 22/7 * (7/2)^2 * 14
= 539 cm^3......
2nd Cylinder's volume = 22/7 * 7^2 * 7
= 1078 cm^3....
As we can see, Volume of 2nd cylinder is greater than the 1st one.....
NOW, SURFACE AREA
1st one has a surface area of 308 cm^2...
2nd one has a surface area of 308 cm^2...
Thus, it's not necessary that the one with greater volume will have more surface area...
Comment in case of any queries....
Answer:
Cylinder B
Step-by-step explanation:
Cylinder A:
Diameter d = 7 cm.
∴Radius = d/2 = 3.5 cm
Height = 14 cm.
We know that Volume of cylinder = πr²h
= (22/7) * (3.5)² * 14
= 539 cm³.
Cylinder B:
Diameter d = 14 cm.
∴ Radius = 7 cm.
Height = 7 cm.
Volume of cylinder = πr²h
= (22/7) * (7)² * 7
= 1078 cm³
Therefore, Volume of cylinder B is greater than Cylinder A.
Total surface area:
Cylinder A = 2πr(r + H)
= 2 * 22/7 * 3.5 * (17.5)
= 385 cm².
Cylinder B = 2π(r + H)
= 2 * 22/7 * 7 * (14)
= 616 cm²
Therefore, Surface area of cylinder B is greater.
∴ Cylinder with greatest volume also has greater surface area.
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