Question

please help me with this logatithm problem​

Answer 1

logx/2 = logy/3 = logz/5

yz = x(?)

logx/2 = logy/3 -----> eq1

logx/2 = logz/5 -----> eq2

From eq1

logx/2 = logy/3 -----> eq1

3logx = 2logy

loga^n = nloga

logx^3 = logy^2 -----> eq3

From eq2

logx/2 = logz/5 -----> eq2

5logx = 2logz

loga^n = nloga

logx^5 = logz^2 -----> eq4

add both eq3 and eq4

logx^3 + logx^5 = logy^2 + logz^2

loga^m + loga^n = loga^(m+n)

loga^m + logb^m = log(a.b) ^m

log(x)^8 = log(y.z)^2

loga^n = nloga

8logx = 2log(y.z)

4logx = log(y.z)

logx^4 = log(y.z)

x^4 = y. z

option 4 is correct

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