Question

please help me with this. only (d) no.


2g of magnesium is burnt in a close vessel containing 3g of oxygen
a. Which one is limiting reaction?
b. Calculate the mole of reactant left over
c. How many gram of MgO are produced?
d. What is the mass of H2SO4 required to neutralize MgO formed in the
reaction.

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Answer 1

MgO + H₂SO₄ → MgSO₄ + H₂O

mass of MgO = 24 + 16 = 40 g

mass of H₂SO₄ = 2 + 32+ 16× 4 = 98 g

MgO formed in above reaction = 3.34 g

40 g MgO reacts with → 98 g H2SO4

1 g MgO reacts with → 98/40 g H2SO4

3.34 g MgO reacts with → 98/40 × 3.34 = 6.81 g H2SO4