Question

please help me with this out​

Answer 1

Answer:

$12 \{\frac{x + 3}{2} - \frac{x + 3}{4} \} = \frac{x - 1}{2} \\ 12 (x+3)\{\frac{1}{2}- \frac{1}{4}\} =\frac{x-1}{2} </p><p> \\ 12 (x+3)\{\frac{2 }{4}- \frac{1}{4}\} =\frac{x-1}{2}</p><p> \\ 12 (x+3)\{\frac{2-1}{4}\} =\frac{x-1}{2}</p><p> \\ 12 (x+3)\{\frac{1 }{4}\} =\frac{x-1}{2}</p><p> \\ \frac{12}{4}(x+3)=\frac{x-1}{2}\\</p><p>3(x+3)=\frac{x-1}{2}\\</p><p>3x + 9=\frac{x-1}{2}\\</p><p>2 (3x+9)=x-1\\</p><p>6x + 18= x - 1\\</p><p>6x - x = - 1-18\\</p><p>5 x =-19\\</p><p>x = \frac{-19}{5}$