please help me with this physics problem
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Hope it helps. If answer is wrong please tell me.
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shr15:
thanks ur ans. is correcy
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Hey dear here is your answer!!!!
Given:- u = 72 km/hr => 20m/s
a= -2 m/ s^2
v = 0
s= ?
=> v^2 - u ^2 = 2as
=> 0-400 = 2*(-2)(s)
=>100m = s
a) Distance travelled is 100m
______________________________
=> v = u + at
=> 0 = 20+(-2)t
=> 2t = 20
=> t = 10 s
b) time taken = 10 seconds
____________________________
At t = 1 sec
=> S= u + 1/2 a ( 2n-1)
=> S = 20 + (-1)(2-1)......{ n = 1 sec }
=> S = 20-1
=> S = 19 m
_______
At t = 3 sec
=> S = u + 1/2 a (2n-1)
=> S = 20+(-1)(6-1)......{n= 3 sec }
=> S = 20-5
=> S = 15 m
c) answer is 18&15 m respectively
___________________________
Hope it helps u dear...☺️☺️☺️☺️
Given:- u = 72 km/hr => 20m/s
a= -2 m/ s^2
v = 0
s= ?
=> v^2 - u ^2 = 2as
=> 0-400 = 2*(-2)(s)
=>100m = s
a) Distance travelled is 100m
______________________________
=> v = u + at
=> 0 = 20+(-2)t
=> 2t = 20
=> t = 10 s
b) time taken = 10 seconds
____________________________
At t = 1 sec
=> S= u + 1/2 a ( 2n-1)
=> S = 20 + (-1)(2-1)......{ n = 1 sec }
=> S = 20-1
=> S = 19 m
_______
At t = 3 sec
=> S = u + 1/2 a (2n-1)
=> S = 20+(-1)(6-1)......{n= 3 sec }
=> S = 20-5
=> S = 15 m
c) answer is 18&15 m respectively
___________________________
Hope it helps u dear...☺️☺️☺️☺️
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