Question

please help me with this problem:
$\frac{x+9}{28}+\frac{x-4}{3} = \frac{5x-32}{9} +\frac{2x-3}{35}$

Answer 1

$\frac{x+9}{28} + \frac{x-4}{3} =\frac{5x-32}{9} + \frac{2x-3}{35} \\\\( taking LCM\ on\ both\ sides\we\ will \get \ get )\\\\\frac{3x + 27 + 28 x - 112}{84} = \frac{175 x - 1120+ 18 x - 27}{315} \\\\\frac{31 x - 83 }{84} = \frac{193 x -1147}{315} \\\\( cross multiplying )\\\\9765 x - 26145 = 9135 x - 32445\\\\630 x = - 6300\\\\x = - 10$

HENCE, the value of x will be -10

Answer 2

Answer:

\begin{align*}2x^2 + 3x + 1 = 0\end{align*} ... a)\begin{align*} \text{ Quadratic formula:} && x &= \frac{-b \pm ... + 1}{ 4} \ \ \text{and} \ \ x = \frac{-3 - 1}{4}\\ \text{Solve :} && x ...