Please help me with this question.....
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x2+x+3
sum of zeroes = a +b=-b/a
=-1/1
product of zeroes =ab=c/a
=3/1
now, a^2+b^2
(a+b)^2=a^2+b^2+2ab
(-1)^2=a^2+b^2+2×3
1=a^2+b^2+6
a^2+b^2=-5
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Answer:
sum of zeroes is alpha + beta = -b/a
product of zeroes is alpha×beta=c/a
here a=1 b=1 and c=3
so alpha + beta=-1/1=-1
and alpha×beta=3/1=3
put these values in the following equation you will get respective answers
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