Question

Please help me with this question!​

Answer 1

Answer:

Step-by-step explanation:Angle z + angle OAB = 90°

( Since the tangent and radii are perpendicular to each other)

Angle z + 50° = 90°

So, Angle z = 40°

OA = OB. (equal radii)

So, OAB is a isosceles triangle.

Angle OAB = angle OBA = 50°

In triangle OAB,

by angle sum property of triangles,

Angle OAB + Angle OBA +Angle AOB =180°

50° +50° + angle y = 180°

So, Angle y = 80°

Angle OAT = 90°

In triangle OAT

By angle sum property of triangles,

Angle OAT + angle AOT + angle OTA = 180°

90° + 80° + angle t =180°

Angle t = 10°