Question

please help me with this question ​

Answer 1

$x {}^{2} + px + q = = x {}^{2} + (a + b)x + ab \\ therefore \: \: ....compairing \: both \: sides... \: \\ p = (a + b) \\ q = ab$

now......

$x { }^{2} + pxy + qy {}^{2} \\ = > x {}^{2} + (a + b)xy + aby {}^{2} \\ = > x {}^{2} + a xy + bxy + aby {}^{2} \\ = > x(x + ay) + by(x + ay) \\ = > (x + ay)(x + by)$