Question

please help me with this question​

Answer 1

Answer:

Step-by-step explanation:

i) Let no. of books be y

So, $40=$xy

        y=40/x

So, no. of books bought=40/x

ii)Cost per book=x+2

No. of books bought with $40=40/x-1

                                   

                     $\frac{40}{x+2} =\frac{40}{x} -1\\\\\frac{40}{x+2} =\frac{40-x}{x}\\\\40x=(40-x)(x+2)\\40x=40x+80-x^2-2x\\x^2+2x-80=40x-40x\\x^2+2x-80=0$

Proven.