Please help me with this question.
Attachments:
Answers
Answered by
1
Heya friend ,
Here is your answer !!
_________
Given , that the fig. HOPE is a parallelogram .
We know , that in a parallelogram , the opposite angles are equal .
So , acc. to the figure ,
42° = x + 2x + 3x
=> 42° = 6x
=> 7° = x .
Now , angle OHE and angle HEP sum up to 180 ° and angle HEP is 42°
So , acc. to the diagram ,
180° = angle OHE + 42°
=> angle OHE = 180° - 42°
=> angle OHE = 138° .
Now , x + y + angle OHE = 180° ( since they are the three angles of a triangle ) .
So , x + y + angle OHE = 180°
=> 7° + y + 138° = 180°
=> y + 145° = 180°
=> y = 35° . [ answer ]
________
Hope it helps
Here is your answer !!
_________
Given , that the fig. HOPE is a parallelogram .
We know , that in a parallelogram , the opposite angles are equal .
So , acc. to the figure ,
42° = x + 2x + 3x
=> 42° = 6x
=> 7° = x .
Now , angle OHE and angle HEP sum up to 180 ° and angle HEP is 42°
So , acc. to the diagram ,
180° = angle OHE + 42°
=> angle OHE = 180° - 42°
=> angle OHE = 138° .
Now , x + y + angle OHE = 180° ( since they are the three angles of a triangle ) .
So , x + y + angle OHE = 180°
=> 7° + y + 138° = 180°
=> y + 145° = 180°
=> y = 35° . [ answer ]
________
Hope it helps
Similar questions