Question

please help me with this question.

Answer 1

Answer:

i. = 3Ω

4Ω+2Ω = 6Ω

then divide that by the other circuit in the parallel series which gives you :

$\frac{1}{6} + \frac{1}{6} = \frac{1}{0.333333333}$

now get the reciprocal of 1/0.333333333

$\frac{1}{0.333333333} = 3$

ii.

i = v/r

i = 6/3

i = 2V

iii.

not sure about this sorry.