Question

please help me with this question ....​

Answer 1

$\huge\sf\blue{Given}$

✭ BE & CF are Altitudes

✭ AB = AC

$\rule{110}1$

$\huge\sf\gray{To\;Prove}$

◈ BE = CF

$\rule{110}1$

$\huge\sf\purple{Steps}$

Things to be kept in mind

»» It is an Isosceles triangle (two sides are equal)

»» So when we have to prove that a side in them is equal then better chose a triangle with the equal sides as a part (Here ∆ACF & ∆ABE)

»» Always look if there are anything common in both the triangles

In ∆ACF & ∆ABE

➢ $\sf AB = AC \: \bigg\lgroup Given \bigg\rgroup$

➢ $\sf\angle A = \angle A\:\bigg\lgroup Common\bigg\rgroup$

➢ $\sf \angle AFC = \angle AEB\bigg\lgroup 90^{\circ} \bigg\rgroup$

➢ $\sf\triangle ACF \cong \triangle ABE \bigg\lgroup ASA \bigg\rgroup$

$\sf\therefore BE = CF \: \bigg\lgroup CPCT \bigg\rgroup$

$\sf Hence \ Proved !!$

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Answer 2

Just prove that the triangles are equal that's all, bye heeeeee