Question

Please help me with this question

Answer 1

Answer:

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Explanation:

u = 18km/h = 5m/s

v = 54km/h = 15m/s

s = 200m

so, 2as=v^2 - u^2

     2(a)(200)= (15)^2 - (5)^2

     400a = 225 - 25

            a = 200/400

            a = 0.5m/s

So, acceleration of the car is 0.5m/s when it leaves the curved road