Math, asked by GreatAniruddh7, 1 year ago

please help me with this question 2morro is my exam please ​

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Answered by ranjankumar5541
2

Step-by-step explanation:

given that-AB=AD

CB=CD

E, F, and G are mid point on side

AB, AD andCD

construction join AC and BD and bisect<A Perpendicular to BD name it I

prove-

in AIB and AID

AB=AD

<AIB=<AID [90°]

AI=AI (COMMON SIDE)

AIB~AID

we know that

inAIB INAID AE/BE=AJ/IJ. 1 AF/DF=AJ/

IJ 2

in eq 1.and 2

AE/BE=AF/DF

SO EF||BD AND EG IS A TRANSVERSAL

<F=<G=90°

ii. draw a||lineGH that parallel to BD

so BD||GH

BC=DC

so H bisect CB

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