Question

please help me with this question.​

Answer 1

In △AOB

OA=OB

∴∠OAB+∠OBA+∠AOB=180

=>2∠OAB+90 =180

=>2∠OAB=180 −90

=>∠OAB= 90/2

=45

We know that the angle subtended at the centre of the circle by an arch is twice the angle subtended at the circumference by the same arc.

∴∠ACB= 1/2∠AOB

= 90/2

=45

Again in △ABC

∠ACB+∠CBA+∠CAB=180

=>45 +30 +∠CAB=180

=>∠CAB=180 -75

=105

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