Question

please help me with this question ​

Answer 1

Let us assume the mass of compound = 100 gm.

Mass of carbon = 40 gm
Moles of carbon
12
40
​


Mass of hydrogen = 6.66 gm
Moles of hydrogen =
1
6.66
​


Mass of oxygen = 53.34 gm
Moles of oxygen
16
53.34
​


Ratio of moles = C:H:O=
12
40
​
:
1
6.66
​
:
16
53.34
​
=1:2:1

Therefore, the empirical formula is CH
2
​
O.