Question

please help me with this question​

Answer 1

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Answer 2

In these types of circuits, we will assign potential drops across each capacitor.

• Refer to 1st diagram !

Now, we will simplify the circuit as shown in 2nd diagram.

So, we can identify a balanced wheatstone bridge in the upper part , so capacitor CD is removed.

Now, arrangement of capacitor:

• AC and CB in series
• AD and DB in series
• AB in lower segment

• And all the above in parallel !

$\rm C_{net} = \dfrac{1}{2} + \dfrac{1}{2} + 1$

$\rm \implies C_{net} = 1+ 1$

$\rm \implies C_{net} = 2 \: \mu F$

So, net capacitance is 2 uF.