Question

please help me with this question​

Answer 1

Answer:

I) AB Part of the graph shows accelerated motion

II)CD Part of the graph shows retarded motion

III)

$s = (u + v) \div 2t$

so s=(0+4)/2*4=0.5 metre

so distance traveled by the body in first 4 second is 0.5 metres

Answer 2

Answer:

i) From A to B

ii)From C to D

iii)4m/s²

Explanation:

i)As object starts from A, it means that in A position the object was in rest. Then it's velocity and time increased. So, acceleration will also increased.

ii) In position C to D, the graph shows that it's velocity is decreasing as per time. So, retardation will happen.

iii)Distance = 4m, as per graph