Question

please Help me with this question​

Answer 1

Step-by-step explanation:

Given:

$\sqrt{6} {x}^{2} y + (2x + \sqrt{6})y + 3xy$

To find: Given expression is equal to?

Solution:

Step 1: Analyze the expression

In all the three terms y is present.

Step 2: Take y common from all terms

$y(\sqrt{6} {x}^{2} + (2x + \sqrt{6}) + 3x)$

Step 3: Add similar terms

$y(\sqrt{6} {x}^{2} + 5x + \sqrt{6} )$

Step 4: factorise

$y( \sqrt{6} {x}^{2} + 3x + 2x + \sqrt{6} ) \\ \\or \\ \\ y( \sqrt{3} \sqrt{2} {x}^{2} + \sqrt{3} \sqrt{3} x + \sqrt{2} \sqrt{2} x + \sqrt{3} \sqrt{2} )$

rewriting the terms.

Step 5: Take common

$y( \sqrt{3}x( \sqrt{2} {x} + \sqrt{3} ) + \sqrt{2} (\sqrt{2} x + \sqrt{3} ) ) \\ \\ or \\ \\ y( \sqrt{2} x + \sqrt{3} )( \sqrt{3}x + \sqrt{2} )$

Final answer:

$\bold{\red{y( \sqrt{2} x + \sqrt{3} )( \sqrt{3}x + \sqrt{2} )}}$

Option (2) is correct.

Hope it helps you.

To learn more on brainly:

2) 6x²:7x- I is a quadratic equations. Write values of a, b, c.

https://brainly.in/question/45594910