please help me with this question and kindly show the steps
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maximum velocity----
v=0+at=2(10)=20m/s
retardation ------
v=u-at⇒0=20-a(50)⇒a=(2/5)m/s²
total distance -----
1/2*2*(10)² +20(200)+{20*50-1/2(2/5*50²)=100+4000+(1000-500)=4600m
average velocity = total distance/total time=4600/260=230/13
v=0+at=2(10)=20m/s
retardation ------
v=u-at⇒0=20-a(50)⇒a=(2/5)m/s²
total distance -----
1/2*2*(10)² +20(200)+{20*50-1/2(2/5*50²)=100+4000+(1000-500)=4600m
average velocity = total distance/total time=4600/260=230/13
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