Question

Please help me with this question

Dont spam plss

Answer 1

Answer:

EASY BRO!!!

Step-by-step explanation:

Look at triangle CBE

here use the theorem that, when a line parallel to one side of the triangle joins the other two sides at their midpoints.

You know that D is midpoint of BC right? because AD is median

so DF joins EC at F which is midpoint of EC

now AC/2 = EC

and EC/2 = FC

EC = 2FC

AC/2 = 2FC

or

AC/4 = FC

easy eh?

good day to you

Answer 2

Step-by-step explanation:

Given,

AD and BE are medians of ΔABC.

Hence, in ∆ABC, we have:

AC = AE + EC

But,

AE = EC [∵ E is midpoint of AC]

∴ AC = 2EC   ------- (1)

Now in ∆BEC,

DF || BE

Also,

EF = CF [∵ as D is the midpoint of BC]

But,

EC = EF + CF

∴ EC = 2 CF   ------- (2)

From (1) and (2), we get

=> AC = 4 CF

CF = (1/4) AC

Hope it helps!