Please help me with this question from pulley constraints (class 11 Newton's laws of motion) as soon as possible
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Please help me with this question from pulley constraints (class 11 Newton's laws of motion) as soon as possible
Answered by
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Answer:
Explanation:
let velocity of block 3 = v3 downward
therefore velocity in one of the hand = 2v3
velocity of block 2 = v2 downward
therefore velocity in one of the hand = 2v2
velocity of block m1 = v2+v3 left
v1=v2+v3
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