Question

please help me with this question =>

Answer 1

Answer:

5

Step-by-step explanation:

let

$x = \sqrt{5 } \sqrt[4]{5} \sqrt[8]{5} ... \infty \\ squaring \: both \: sides \\ {x}^{2} = 5( \sqrt{5} \sqrt[4]{5} \sqrt[8]{5} ... \infty ) \\ or \: {x}^{2} = 5x \\ x = 5$

On solving this quadratic equation x can also be zero, but on observing, we can conclude that x cannot be zero

So x will be 5

Hence five is your answer.

Answer 2

Answer:

here's ur answer in the attachment