Question

please help me with this question in written form need step by step simple answer. this is class 8 maths.​

Answer 1

ANSWER : 30

Step-by-step explanation:

$( \frac{1}{6} - \frac{1}{8} ) {}^{ - 1} + ( \frac{1}{2} - \frac{1}{3} ) {}^{ - 1}$

$→ \: ( \frac{4}{24} - \frac{3}{24} ) {}^{ - 1} + ( \frac{3}{6} - \frac{2}{6} ) {}^{ - 1} \\ → \: ( \frac{4 - 3}{24} ) {}^{ - 1} + ( \frac{3 - 2}{6} \: \ ) {}^{ - 1} \\ → \: ( \frac{1}{24} ) {}^{ - 1} + ( \frac{1}{6} \: \ ) {}^{ - 1}$

→ 24 + 6

→ 30

Answer 2

$\large\ \pmb{\red{«\: คꈤ \mathfrak Sฬєя \: » }}( 6 ^ { - 1 } - 8 ^ { - 1 } ) ^ { - 1 } + ( 2 ^ { - 1 } - 3 ^ { - 1 } ) ^ { - 1 } \\ \\⇛ \left(\frac{1}{6}-8^{-1}\right)^{-1}+\left(2^{-1}-3^{-1}\right)^{-1} \\ \\⇛ \left(\frac{1}{6}-\frac{1}{8}\right)^{-1}+\left(2^{-1}-3^{-1}\right)^{-1} \\ \\⇛ \left(\frac{1}{24}\right)^{-1}+\left(2^{-1}-3^{-1}\right)^{-1} \\ \\⇛ 24+\left(2^{-1}-3^{-1}\right)^{-1} \\ \\⇛ 24+\left(\frac{1}{2}-3^{-1}\right)^{-1} \\ \\⇛ 24+\left(\frac{1}{2}-\frac{1}{3}\right)^{-1} \\ \\ ⇛24+\left(\frac{1}{6}\right)^{-1} \\ \\ ⇛24+6 \\ \\⇛ 30$

$\: \: \: \: \: \: \: \: \: \: \huge \bold{@WildCat7083 }$