Physics, asked by harnoorkaurtutejahar, 3 months ago

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Answered by mahanteshgejji
1

Answer:

distance = 14 m

Explanation:

u = 0

In first two seconds the car moves with uniform accln of 2 m/s²

S₁ = 1/2x 2 x 4. ( s = ut + 1/2 at²)

S₁ = 4 m

Velocity after 2 sec is

v= 2x2 = 4 m/s (v = u + at)

In next two seconds it moves with constant a = 1 m/s²

S₂ = 4x 2 + 1/2 x 1 x 4

= 8 +2

= 10

∴ total dist = S₁ + S₂ = 14 m

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