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Answer:
distance = 14 m
Explanation:
u = 0
In first two seconds the car moves with uniform accln of 2 m/s²
S₁ = 1/2x 2 x 4. ( s = ut + 1/2 at²)
S₁ = 4 m
Velocity after 2 sec is
v= 2x2 = 4 m/s (v = u + at)
In next two seconds it moves with constant a = 1 m/s²
S₂ = 4x 2 + 1/2 x 1 x 4
= 8 +2
= 10
∴ total dist = S₁ + S₂ = 14 m
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